3. Construct ΔABC with BC = 7.5 cm, AC = 5 cm and m ∠C = 60o.
Step 1. Draw a line segment BC = 7.5 cm.
Step 2. Consider point C as centre to make an angle of 60o. Now, draw a ray CX, i.e. ∠XCB = 60o.
Step 3. Along CX, set off AC = 5cm.
Step 4. Join AB.
Hence, ΔABC is the required triangle.