# Mathematics Class 7 Chapter 2- Exercise 2.5 – Fractions and Decimals

1. Which is greater?

(i) 0.5 or 0.05

Solution:

We compare the tenth place digit:

So, 5 > 0

Hence, 0.5 > 0.05

(ii) 0.7 or 0.5

Solution:

We compare the tenths place digit:

so, 7 > 5

Hence, 0.7 > 0.5

(iii) 7 or 0.7

Solution:

We compare the one’s place digit:

so, 7 > 0

Hence, 7 > 0.7

(iv) 1.37 or 1.49

Solution:

we compare the tenths place digit:

So, 3 < 4

Hence, 1.37 < 1.49

(v) 2.03 or 2.30

Solution:

We compare tenths place digit:

So, 0 < 3

Hence, 2.03 < 2.30

(vi) 0.8 or 0.88

Solution:

we write it as 0.80 or 0.88

since here tenth place is the same

so, we compare the hundredth place:

we get 0 < 8

Hence, 0.80 < 0.88

2. Express as rupees as decimals:

(i) 7 paise

Solution:

(ii) 7 rupees 7 paise

Solution:

(iii) 77 rupees 77 paise

Solution:

(iv) 50 paise

Solution:

(v) 235 paise

Solution:

3. (i) Express 5 cm in meter and kilometer

Solution:

(ii) Express 35 mm in cm, m and km

Solution:

4. Express in kg:

(i) 200 g

Solution:

(ii) 3470 g

Solution:

(iii) 4 kg 8 g

Solution:

5. Write the following decimal numbers in the expanded form:

(i) 20.03

Solution:

(ii) 2.03

Solution:

(iii) 200.03

Solution:

(iv) 2.034

Solution:

6. Write the place value of 2 in the following decimal numbers:

(i) 2.56

Solution:

Place value of 2 in 2.56 is ones

(ii) 21.37

Solution:

Place value of 2 in 21.37 is tens

(iii) 10.25

Solution:

Place value of 2 in 10.25

2/10 = 0.2

So, place value of 2 is tenths

(iv) 9.42

Solution:

Place value of 2 in 9.42

2/100 = 0.02

So, place value of 2 is hundredths

(v) 63.352

Solution:

Place value of 2 in 63.352

2/1000 = 0.002

So, place value of 2 is thousandths

7. Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?

Solution:

Given,

Distance from A to B = 7.5 km

Distance from B to C = 12.7 km

Distance travelled by Dinesh = AB + BC

= 7.5 km + 12.7 km

= 20.2 km

Now, Given

Distance from A to D = 9.3 km

Distance from D to C = 11.8 km

Dstance travelled by Ayub from A to C = AD + DC

= 9.3 km + 11.8 km

= 21.1 km

So, 21.1 > 20.2

= 21.1km – 20.2km

=0.9 km

Hence Ayub travelled more distance than Dinesh by 0.9km

8. Shyama bought 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala bought 4 kg 800 g oranges and 4 kg 150 g bananas. Who bought more fruits?

Solution:

Given,

Shyama bought

Apple = 5 kg 300 g

Mangoes = 3 kg 250 g

Now, Total fruits bought by Shyama = 5 kg 300 g apple + 3 kg 250 g mangoes

= 5.300 kg apple + 3.250 kg mangoes (convert gram into kg)

=8.550 kg of fruits

Given,

Sarala bought

Oranges = 4 kg 800 g

Bananas = 4 kg 150 g

Now, Total fruits bought by Sarala = 4 kg 800 g oranges + 4 kg 150 g bananas

= 4.800 kg oranges + 4.150 kg bananas (convert gram into kg)

= 8.950 kg of fruits

So,

8.950 kg > 8.550 kg

Hence, Sarala bought more fruits than Shyama.

9. How much less is 28 km than 42.6 km?

Solution:

Given, 28 km < 42.6

Now,

= 42.6 km – 28 km

= 14.6 km

Hence, 28 km is les than 42.6 km by 14.6 km

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