1. Which is greater?
(i) 0.5 or 0.05
Solution:
We compare the tenth place digit:
So, 5 > 0
Hence, 0.5 > 0.05
(ii) 0.7 or 0.5
Solution:
We compare the tenths place digit:
so, 7 > 5
Hence, 0.7 > 0.5
(iii) 7 or 0.7
Solution:
We compare the one’s place digit:
so, 7 > 0
Hence, 7 > 0.7
(iv) 1.37 or 1.49
Solution:
we compare the tenths place digit:
So, 3 < 4
Hence, 1.37 < 1.49
(v) 2.03 or 2.30
Solution:
We compare tenths place digit:
So, 0 < 3
Hence, 2.03 < 2.30
(vi) 0.8 or 0.88
Solution:
we write it as 0.80 or 0.88
since here tenth place is the same
so, we compare the hundredth place:
we get 0 < 8
Hence, 0.80 < 0.88
2. Express as rupees as decimals:
(i) 7 paise
Solution:

(ii) 7 rupees 7 paise
Solution:

(iii) 77 rupees 77 paise
Solution:

(iv) 50 paise
Solution:

(v) 235 paise
Solution:

3. (i) Express 5 cm in meter and kilometer
Solution:

(ii) Express 35 mm in cm, m and km
Solution:

4. Express in kg:
(i) 200 g
Solution:

(ii) 3470 g
Solution:

(iii) 4 kg 8 g
Solution:

5. Write the following decimal numbers in the expanded form:
(i) 20.03
Solution:

(ii) 2.03
Solution:

(iii) 200.03
Solution:

(iv) 2.034
Solution:

6. Write the place value of 2 in the following decimal numbers:
(i) 2.56
Solution:
Place value of 2 in 2.56 is ones
(ii) 21.37
Solution:
Place value of 2 in 21.37 is tens
(iii) 10.25
Solution:
Place value of 2 in 10.25
2/10 = 0.2
So, place value of 2 is tenths
(iv) 9.42
Solution:
Place value of 2 in 9.42
2/100 = 0.02
So, place value of 2 is hundredths
(v) 63.352
Solution:
Place value of 2 in 63.352
2/1000 = 0.002
So, place value of 2 is thousandths
7. Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?
Solution:
Given,
Distance from A to B = 7.5 km
Distance from B to C = 12.7 km
Distance travelled by Dinesh = AB + BC
= 7.5 km + 12.7 km
= 20.2 km
Now, Given
Distance from A to D = 9.3 km
Distance from D to C = 11.8 km
Dstance travelled by Ayub from A to C = AD + DC
= 9.3 km + 11.8 km
= 21.1 km
So, 21.1 > 20.2
= 21.1km – 20.2km
=0.9 km
Hence Ayub travelled more distance than Dinesh by 0.9km
8. Shyama bought 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala bought 4 kg 800 g oranges and 4 kg 150 g bananas. Who bought more fruits?
Solution:
Given,
Shyama bought
Apple = 5 kg 300 g
Mangoes = 3 kg 250 g
Now, Total fruits bought by Shyama = 5 kg 300 g apple + 3 kg 250 g mangoes
= 5.300 kg apple + 3.250 kg mangoes (convert gram into kg)
=8.550 kg of fruits
Given,
Sarala bought
Oranges = 4 kg 800 g
Bananas = 4 kg 150 g
Now, Total fruits bought by Sarala = 4 kg 800 g oranges + 4 kg 150 g bananas
= 4.800 kg oranges + 4.150 kg bananas (convert gram into kg)
= 8.950 kg of fruits
So,
8.950 kg > 8.550 kg
Hence, Sarala bought more fruits than Shyama.
9. How much less is 28 km than 42.6 km?
Solution:
Given, 28 km < 42.6
Now,
= 42.6 km – 28 km
= 14.6 km
Hence, 28 km is les than 42.6 km by 14.6 km