Construct the following quadrilaterals.
(i) Quadrilateral LIFT
LI = 4 cm
IF = 3 cm
TL = 2.5 cm
LF = 4.5 cm
IT = 4 cm
Solution:
Construction steps:
Step I: Draw a line segment LI = 4 cm.
Step II: With centre I draw an arc of radius 3 cm.
Step III: With centre L draw another arc of radius 4.5 cm to meet the former arc at F.
Step IV: Join LF and IF.
Step V: Draw an arc with centre L and radius 2.5 cm.
Step VI: Draw another arc with centre I and radius 4 cm to meet the previous arc at T.
Step VII: Join LT and IT.
Hence, LIFT is the required quadrilateral.
(ii) Quadrilateral GOLD
OL = 7.5 cm
GL = 6 cm
GD = 6 cm
LD = 5 cm
OD = 10 cm
Solution:
Constructions steps:
Step I: Draw a line segment OL = 7.5 cm
Step II: With centre O draw an arc of radius 10 cm.
Step III: Draw another arc with centre L and radius 5 cm to meet the previous arc at D.
Step IV: Join OD and LD.
Step V: With centre L draw an arc at D with equal radii of 6 cm to meet each other at G.
Step VI: Join LG and DG.
Hence, GOLD is the required quadrilateral.
(iii) Rhombus BEND
BN = 5.6 cm
DE = 6.5 cm
Solution:
Constructions steps:
(We know that the diagonals of a rhombus bisect each other at the right angle)
Step I: Draw a line segment BN = 5.6 cm.
Step II: At O draw the right bisector of BN.
Step III: Draw two arcs with centre O and radius 12 × DE, i.e., 12 × 6.5 = 3.25 cm to meet the right bisector at D and E.
Step IV: Join BE, EN, ND and BD.
Hence, BEND is the required rhombus.
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