1. For which of these would you use a histogram to show the data?
(a) The number of letters for different areas in a postman’s bag.
(b) The height of competitors in an athletics meet.
(c) The number cassettes produced by 5 companies.
(d) The number of passengers boarding trains from 7.00 a.m. to 7.00 p.m. at a station.
Give reason for each.
Solution:
We know that Histogram is a graphical representation of data if the data represented using class- interval.
Now,
a) Here the number of areas cannot be represented in class-intervals. So, we cannot use the histogram to show the data.
b) The height of competitors can be divided into intervals. Hence, here we can use histogram.
c) Here companies cannot be divided into intervals. That’s why we cannot use histogram.
d) The time for boarding the train can be divided into intervals. Hence, here we can use histogram.
2. The shoppers who come to a departmental store are marked as: man (M), woman (W), boy (B) or girl (G). The following list gives the shoppers who came during the first hour in the morning.
W W W G B W W M G G M M W W W W G B M W B G G M W W M M W W W M W B W G M W W W W G W M M W M W G W M G W M M B G G W.
Make a frequency distribution table using tally marks. Draw a bar graph to illustrate it.
Solution:
3. The weekly wages (in ₹) of 30 workers in a factory are:
830, 835, 890, 810, 835, 836, 869, 845, 898, 890, 820, 860, 832, 833, 855, 845, 804, 808, 812, 840, 885, 835, 835, 836, 878, 840, 868, 890, 806, 840.
Using tally marks, make a frequency table with intervals as 800 – 810, 810 – 820 and so on.
Solution:
4. Draw a histogram for the frequency table made for the data in Question 3 and answer the following questions.
(i) Which group has the maximum number of workers?
(ii) How many workers earn ₹ 850 and more?
(iii) How many workers earn less than ₹ 850?
Solution:
(i) 830-840 is the group having maximum number of workers i.e 9, compared to other groups.
(ii) Earning of workers ₹ 850 and more= 1+3+1+1+4=10
(iii) Earning of workers less than ₹ 850= 3+2+1+9+5=20
5. The number of hours for which students of a particular class watched television during holidays is shown through the given graph.
Answer the following:
(i) For how many hours did the maximum number of students watch T.V.?
(ii) How many students watched TV for less than 4 hours?
(iii) How many students spent more than 5 hours in watching TV?
Solution:
(i) 32 students watched T.V for 4-5 hours.
Hence, the maximum number of students who watched T.V. for 4 – 5 hours.
(ii) The total number of students who watched T.V. less than 4 hours= 22+8+4=34
(iii) The total number of students who spent more than 5 hours in watching TV
=8+6=14
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